HSC Chemistry

Percentage Composition by Mass: Classification of Matter and Separation Techniques

Published 2026-09-10 · Updated 2026-09-10

Percentage composition questions look deceptively simple, and that is exactly why students drop marks on them in the HSC examination. A single arithmetic slip, or forgetting to use the total mass of the mixture rather than the mass of just one component, can cost you a mark that felt certain. Worse, many students can recite the formula but freeze when the question runs it in reverse, asking for the mass of a sample given a known percentage. This post walks through everything you need, clearly and completely.

What the syllabus asks

Within the concept of Classification of Matter and Separation Techniques, you are expected to understand how mixtures are described quantitatively. Specifically, you need to be able to:

The idea, explained

What is a mixture?

A mixture contains two or more substances physically combined, with no fixed composition. Because the proportions can vary, chemists need a way to describe how much of each component is present. Percentage by mass is the standard way to do this.

The formula

% by mass = (mass of component / total mass of mixture) × 100

The total mass is the mass of the entire mixture, not just the other components. Keep that denominator correct and you will avoid the most common error.

Forward calculation: finding the percentage

Suppose you have a 200 g soil sample and you separate out 30 g of sand by sieving.

% sand = (30 / 200) × 100 = 15%

The remaining material makes up the rest:

% other material = 100 − 15 = 85%

This is exactly the kind of result you would record in a practical investigation after measuring mass before and after separation.

Reverse calculation: finding a mass

Sometimes the HSC examination gives you the percentage and asks you to find a mass. The same formula rearranges neatly.

Imagine a 500 g seawater sample is evaporated and 17.5 g of salt is recovered.

% salt = (17.5 / 500) × 100 = 3.5%

Now suppose a second seawater sample of unknown mass must contain 10.5 g of salt at the same concentration of 3.5%. Rearrange the formula:

mass of sample = (mass of component / %) × 100 mass of sample = (10.5 / 3.5) × 100 = 300 g

Alternatively, you can think of it as:

mass of component = (% / 100) × total mass

so: 10.5 = (3.5 / 100) × total mass, giving total mass = 300 g.

Both approaches reach the same answer; choose whichever feels more natural under exam conditions.

Connecting to separation techniques

Percentage composition is not just an abstract calculation. In practical investigations, you measure mass before and after each separation step, then use those measurements to calculate percentage composition. For example, after evaporating a salt-water solution to recover salt crystals, you weigh the recovered salt and divide by the original mass of solution. Common sources of error in these investigations include incomplete separation (some solid left behind in the filter paper, for instance), loss of product when transferring between containers, and temperature fluctuations that affect how much solvent is removed during evaporation or distillation. Recognising these errors and explaining how they affect your calculated percentage is a skill HSC markers look for in extended-response questions.

What the exam asks

HSC examination questions on this topic typically:

Always show your working. HSC markers award marks for correct method even when an arithmetic error leads to a wrong final answer.

Common mistakes

If you want to work through these calculations step by step, with instant feedback on every line of working, Avocado's AI-native tutoring service has you covered. Start with the Classification of Matter and Separation Techniques lesson and build the confidence to handle any variation the HSC examination throws at you.